Find the zeros of the function by factoring f(x)=x^2+16x+60

Please show work if you can

-6 and -10

Step-by-step explanation:

First find two numbers that multiply to 60 and add up to 16

these numbers are 6 and 10

then write the numbers in factored form: (x+6) (x+10)

Then set each one equal to zero and solve to find the zeros of the function

x+6=0 --> x=-6

x+10=0 --> x=-10

the zeros of the function are -6 and -10

Hope this helps!

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629