Ben rolled a number cube numbered one through six. It landed on an odd number 30 times. What is the probability that it lands on an odd number on the next roll?

1 /2

Step-by-step explanation:

Sample space of number cube : (1, 2, 3, 4, 5, 6)

Odd numbers on cube : (1, 3, 5) = 3 odd numbers

Since each roll of number cube is independent, the number of times it has landed between fire does not matter :

Therefore, probability of landing on a odd number is :

P = required outcome / Total possible outcomes

P = 3 / 6

P = 1/2

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: