A sequence of 8 numbers is formed such that each term is the product of the two previous terms. Given to terms in the sequence, find the rest of the terms.

Ok so its 1/3, 3, 1, 3, 3, 9, 27, 243

Step-by-step explanation:

So you need 3*3 preceding the 9 because that's the only thing that equals nine when multiplied. And you need ones before that, but you can't just have 1*1*1, cause that would go on forever. So you need a fraction times something that will give you one, and it has to be three if you want to with the rest of the problem.  

If you could, would you mind marking me brainliest?

can i know which language is this?