How are you in the bet nobody’s not going to help me on this question

See below.

Step-by-step explanation:

Party A

y = x^2 + 1

For each value of x in the table, substitute x in the equation with that value and evaluate y.

x = -2: y = (-2)^2 + 1 = 4 + 1 = 5

x = -1: y = (-1)^2 + 1 = 1 + 1 = 2

Do the same for x = 0, x = 1, x = 2

x     y

-2   5

-1    2

0    1

1     2

2    5

Part B

Look at points (-2, 5) and (-1, 2). The change in x from (-2, 5) to (-1, 2) is 1. The change in y is -3.

Now let's look at two other points which have a change in x of 1. Look at points (0, 1) and (1, 2). The change in x from (0, 1) to (1, 2) is 1. The change in y is 1.

You can see that for the first two points, a change of 1 in x produces a change of -3 in y, but for the second two points, the same change of 1 in x produce a change of 1 in y. Since the same change of x does not always produce the same change in y, the function is nonlinear.

A

because they could drop even lower..

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.