There are 20 purple(x) or yellow(y) marbles in a bag. The number of purple marbles is 4 less than 2 times the number of yellow marbles. Write a system of linear equations that represents the situation.

There are 12 purple marbles and 8 yellow marbles.

Step-by-step explanation:

Let there are x purple and y yellow marbled in a bag.

x+y = 20 ...(1)

The number of purple marbles is 4 less than 2 times the number of yellow marbles.

x = 2y -4

x-2y = -4 ...(2)

Subtract equation (1) from (2).

x-2y-(x+y) = -4-20

-2y-y = -24

-3y = -24

y = 8

Put the value of y in equation (1).

x+8 = 20

x = 12

Hence, there are 12 purple marbles and 8 yellow marbles.

the answer is 3/5

step-by-step explanation:

first divide 24 divided by 8 because that is the least common multiple

then divide 40 by 8

then you will get 3/5.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.