Please help i only have 25 min The sum of two consecutive odd integers is more than −12. What is the smallest value that will make this true?

a. Write an inequality that can be used to find the smallest value that will make the statement true.
b. Solve the inequality written in part (a).
C. What is the smallest value that will make this true?

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

vhhhbnbb. ddben jenner v

using pemdas, (order of operations) you'll see the answer is 24.