40 tickets were sold for a concert, some at 75 cents and the rest at $1.25. if the total raiwed was $42, how many had the cheaper ticket​

16 had the cheaper ticket

Step-by-step explanation:

Let the number of 75cents tickets be x

Let the number of $1.25 tickets be y

Since the total tickets is 40, hence;

x+y =40 1

Also if some are sold at 75 cents and the rest at $1.25 with total of $42 earned, then;

0.75x+1.25y = 42... 2

From 1

x = 40-y

Substitute into 2;

0.75(40-y)+1.25y = 42

30-0.75y+1.25y = 42

30+0.5y = 42

0.5y =42-30

0.5y = 12

y = 12/0.5

y = 24

Since x = 40-y

x = 40-24

x = 16

The number of cheaper ticket are 16

$649.60

step-by-step explanation:

i believe it's a.

i'm not sure on this one, most likely correct.