* A helicopter's altitude changes by – 28 ft in 3 s. What is the average change in the helicopter's altitude
each second? Show your work.

-9.33 ft per second

Step-by-step explanation:

To calculate this, you just have to divide -28 by 3. When doing this, it will give the change per second or for every 1 second.

-28/3 = -9.33

Therefore, the average change in the helicopter's altitude each second is -9.33 ft.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

if im not mistaking its

step-by-step explanation: