Please help no one has gave a answer can someone use this equation in the elimination method I’m not sure if it’s 0,0

It's actually not possible to solve this system of equations.

In order to solve for both 'x' and 'y', you need 2 INDEPENDENT equations.  "Independent" means you can't get one of them from the other one.

But in this pair, if you take the second equation, and multiply each side by 3, you get exactly the first equation.  So problem #6 actually gives you only one equation.  If you take either of these and massage it around for a little bit, you get  Y = -1.25x + 1.5 .  For either one.  They're both actually the same equation.

Problem #6 does not define one (X, Y) point.  It defines a line, that crosses the Y-axis at 1.5 and has a slope of -1.25.  EVERY POINT on that line is a solution to the one single equation that they gave you.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°