Find the perimeter and the area of the polygon with the vertices: (-1, -2), (-6, -2), (-6, -8), (-1, -8)

a) The perimeter of the rectangle =

= 22 units

b) The area of the rectangle

= 30 square units

Step-by-step explanation:

We solve the above question using the formula

= √(x2 - x1)² + (y2 - y1)²

When we are given vertices (x1, y1) and (x2, y2)

The vertices: (-1, -2), (-6, -2), (-6, -8), (-1, -8)

We have to find the length of the sides

Side A

(-1, -2), (-6, -2)

= √(-6 - (-1))² +( -2 -(-2))²

= √-5² + 0²

= √25

= 5 units

Side B

(-6, -2), (-6, -8)

= √(-6 - (-6))² + (-8 - (-2))²

= √(-6 +6)² + (-8 +2)²

= √0² + -6²

= √36

= 6 units

Side C

(-6, -8), (-1, -8)

= √(-1 - (-6))² +(-8 - (-8))²

= √(-1 + 6)² + (-8 + 8)²

=√ 5² + 0²

= √25

= 5 units

Side D

(-1, -2), (-1, -8)

= √(-1 -(-1))² + (-8 - (-2))²

= √(-1 + 1)² + ( -8 + 2)²

= √0 + -6²

= √0 + 36

= √36

= 6 units

From the above calculation,

Side A = Side C = 5 units

Side B = Side D = 6 units

Hence, this polygon is a quadrilateral called the RECTANGLE.

Therefore:

a) The perimeter of the rectangle =

2L + 2W

= 2(5) + 2(6)

= 10 units + 12 units

= 22 units

b) The area of the rectangle

= Length × Width

= 5 units × 6 units

= 30 square units

50-60=10

step-by-step explanation:

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right