Let ƒ(x)=−x2+6x−10. Which statement is true regarding the function ƒ(x)?
f(x)=−(x−3)2+1 the function has a minimal value of 1

f(x)=−(x−3)2+1 the function has a maximum value of 1

f(x)=−(x−3)2−1 the function has a minimal value of−1

f(x)=−(x−3)2−1 the function has a maximum value of −1

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!

p

step-by-step explanation:

the answer is "add 2y and y"

step-by-step explanation:

you need to collect the like terms first.