In a race, 22 out of the 25 bicyclists finished in less than 56 minutes. What percent of bicyclists finished the race in less than 56 minutes? Write an equivalent fraction to find the percent. 22 x % % 25 x 100​

uhhm uh i think its uh.. a carrot :/

Step-by-step explanation:

88%

Step-by-step explanation:

22/25 × 4/4 = 88/100 = 88%

congruent segments

step-by-step explanation:

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the 14th row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100