Y=3/2x-9
I need to find the x-intercept and the y-intercept with work plsss

Hi there!

x-int: (6, 0)

y-int: (0, -9)

y = 3/2x - 9

Begin by finding the x-intercept. The x-intercept is located where y = 0, therefore:

0 = 3/2x - 9

Isolate for x by adding 9 to both sides:

9 = 3/2x

Divide both sides by 3/2x:

9 * 2/3 = x

x = 6. Thus, the x-intercept is at (6, 0).

Find the y-intercept by finding the y-value at which x = 0:

y = 3/2(0) - 9

y = -9. The y-intercept is at (0, -9).

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.