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Mathematics, 02.03.2021 17:40 Jasten

\frac{b-3}{3b^2+11b-4}-\frac{2b}{6b ^2+7b-3}=\frac{5}{2a^2+11b+12}

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\frac{b-3}{3b^2+11b-4}-\frac{2b}{6b ^2+7b-3}=\frac{5}{2a^2+11b+12}...
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