Suppose that J and K are points on the number line. If Jk=5 and J lies at -12 where could K be located?

k would be located at

`1234567890-=/*-qwertyuiop[]asdfghjkl; '\\zxcvbnm,./+ /

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi