PLEASE HELP ME Write an inequality for the sum of twice a number and 5 is at most 15. Use y as the variable.

The answer to the problem is 5

Step-by-step explanation:

The sum of twice a number y and 5 is at most 15" can be translated mathematically into the following inequality:

2y + 5 ≤ 15 since the sum, 2y + 5, is at most 15 but could be less than 15.

To solve this inequality for n, proceed as follows:

First, subtract 5 from both sides of the inequality as you would in solving an equation:

2y + 5 - 5 ≤ 15 - 5

2y + 0 ≤ 10

2y ≤ 10

Now, to finally solve the inequality for the variable y, divide both sides of the inequality by 2 as you would in solving an equation:

(2y)/2 ≤ 10/2

(2/2)y ≤ 10/2

(1)y ≤ 5

n ≤ 5 which is all real number less than or equal to 5.

Test Values (y = -1/2, 0, 3, 5, and n = 7):

For y = -1/2:

2y + 5 ≤ 15

2(-1/2) + 5 ≤ 15

-1 + 5 ≤ 15

-4 ≤ 15 (TRUE)

For y = 0:

2y + 5 ≤ 15

2(0) + 5 ≤ 15

0 + 5 ≤ 15

5 ≤ 15 (TRUE)

For y = 3:

2y + 5 ≤ 15

2(3) + 5 ≤ 15

6 + 5 ≤ 15

11 ≤ 15 (TRUE)

For y = 5:

2y + 5 ≤ 15

2(5) + 5 ≤ 15

10 + 5 ≤ 15

15 ≤ 15 (TRUE)

For y = 7:

2y + 5 ≤ 15

2(7) + 5 ≤ 15

14 + 5 ≤ 15

19 ≤ 15 (FALSE)

Therefore, the possible values for y which will make the relevant inequality, 2n + 5 ≤ 15, a true statement are:

{y | y is a real number and y ≤ 5}

where is the page?

step-by-step explanation:

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.