A family has four children. If the genders of these children are listed in the order they are born, there are sixteen possible outcomes: , BBBG, BBGB, BGBB, GBBB, BGBG, GBGB, BGGB, GBBG, BBGG, GGBB, BGGG, GBGG, GGBG, GGGB, and . Assume these outcomes are equally likely. Let represent the number of children that are girls. Find the probability distribution of . Part: 0 / 20 of 2 Parts Complete Part 1 of 2 Your Answer is incorrect (a) Find the number of possible values for the random variable . There are possible values for the random variable .

X : ___ 0 1 2 3 4

P(x): _ 1/16 __ 1/4 3/8 1/4 1/16

Step-by-step explanation:

Given the listed possible occurrence of boys and girls :

B = boys ; G = girls

, BBBG, BBGB, BGBB, GBBB, BGBG, GBGB, BGGB, GBBG, BBGG, GGBB, BGGG, GBGG, GGBG, GGGB, and

Let x = distribution of girls

P = required outcome / Total possible outcomes

For :

x = 0 ;() = 1

P(x) = 1/16

x = 1 ; (BBBG, BBGB, BGBB, GBBB) = 4

P(x) = 4 / 16 = 1/4

P(x = 2) ; (BGBG, GBGB, BGGB, GBBG, BBGG, GGBB) = 6

P(x) = 6 / 16 = 3/8

P(x = 3) ; (BGGG, GBGG, GGBG, GGGB) = 4

P(x) = 4 / 16 = 1/4

P(x = 4) ; () = 1

P(x) = 1 / 16

X : ___ 0 1 2 3 4

P(x): _ 1/16 __ 1/4 3/8 1/4 1/16

a

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