Two cross roads, each of width Sm, run at right angles through the centre of a rectangular park of length 70m and breadth 45m and
parallel to its sides
On the basis of the above information, answer any four of the
following questions​

Rs 57750

Step-by-step explanation:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

​

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

dunno

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.