Solve the following story problem. The perimeter of a rectangle is 60 inches. The length is four times the
width.
What are the length and width of the rectangle?
Define your variables.
X =
Equation 1
y =
Equation 2
What is the length?
what is the width?

The perimeter of a rectangle is equal to 2L + 2W, where L = the length of the rectangle and W = the width of the rectangle. So, one equation is

2L + 2W = 60

From the info given in the problem, we also know that L = 4W. Therefore, we can use the Substitution Method to re-write the first equation as:

4W + 2W = 60

You should be able to solve this equation for W. Once you find W, you can then calculate L.

Step-by-step explanation:

the answer is 1030 it's very simple math.