In ΔMNO, the measure of ∠O=90°, the measure of ∠M=74°, and OM = 5.4 feet. Find the length of NO to the nearest tenth of a foot.

18.8 feet

Step-by-step explanation:

\tan M = \frac{\text{opposite}}{\text{adjacent}}=\frac{x}{5.4}

tanM=

adjacent

opposite

​

=

5.4

x

​

\tan 74=\frac{x}{5.4}

tan74=

5.4

x

​

5.4\tan 74=x

5.4tan74=x

Cross multiply.

x=18.832\approx \mathbf{18.8}\text{ feet}

x=18.832≈18.8 feet

Type into calculator and roundto the nearest tenth of a foot.

M

N

O

5.4

18.8

(adjacent to ∠M)

(opp. of ∠M)

(hypotenuse)

74°

it would to have a graph or something ! but i had this question so its false

step-by-step explanation:

answer: the answer is 5/22

step-by-step explanation: if you subtract 17 from 22 the answer is 5 therefore the remainder of students are female