Suppose that electricity is draining from a capacitor at a rate that is proportional to the voltage, V. across its terminals. If 20% of the electricity has drained after 8.926 seconds, how long will it take the voltage to drop to 10% of its original value?​

The answer you are looking for is right in front of you it’s c. 3/20

(6,1)(5,4)slope = (4 - 1) / (5 - 6) = 3/-1 = -3y = mx + bslope(m) = -3use either of ur , = 6 and y = 1now sub and find b, the y int1 = -3(6) + b1 = -18 + b1 + 18 = b19 = bso ur equation is : y = -3x + we need it in standard formy = -3x + 3x to both sides3x + y = 19 < == standard form

Well it depends, i think b bc yeah

The answer is n divided by -5 + 1