Which of the following equations could you solve by first adding six and then dividing by negative three? 6 - 3 x = -9
+ 6 = -9
-3 x - 6 = -9
3 x - 6 = -9

-3x - 6 = -9    (The third answer)

Step-by-step explanation:

When solving for x, you have to undo each operation. When solving -3x - 6 = -9, you have to undo the -6 first. To do this, add 6 to both sides. Then, you must undo the -3x. To do this, divide by -3 from both sides.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1