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Mathematics, 28.02.2021 19:50 diamondscott9297

Consider the following function and closed interval.
y = 3x^2/3 − 2x, [−1, 1]


Consider the following function and closed interval.
y = 3x^2/3 − 2x, [−1, 1]

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Consider the following function and closed interval.
y = 3x^2/3 − 2x, [−1, 1]
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