If tanx-cotx=5 then what is the value of tan²x+cot²x​

27

Step-by-step explanation:

note that tanx cotx = tanx × = 1

Given

tanx - cotx = 5 ( square both sides )

(tanx - cotx)² = 5² = 25 ← expand left side using FOIL

tan²x - 2tanxcotx + cot²x = 25

tan²x - 2 + cot²x = 25 ( add 2 to both sides )

tan²x + cot²x = 27

the answer is 0.3175 hope that you ^w^

also you might actually want to put this picture up if you want people to solve it luckily i remember this question

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.