three consecutive odd integers are such that three times the smallest is 9 more than twice the largest find the three numbers​

https://www.wyzant.com/resources/answers/732264/three-consecutive-odd-integers-are-such-that-3-times-the-smallest-is-9-more

Step-by-step explanation:

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17, 19, 21

Step-by-step explanation:

let the 3 consecutive odd numbers be n, n + 2 and n + 4 , then

3n = 2(n + 4) + 9 ( 3 times smallest is 9 more than twice the largest )

3n = 2n + 8 + 9

3n = 2n + 17 ( subtract 2n from both sides )

n = 17

n + 2 = 17 + 2 = 19

n + 4 = 17 + 4 = 21

The 3 numbers are 17, 19, 21

the final price would be 29.6925

step-by-step explanation:

39.59 minus 25% equals 29.6925