Find unknown sizes of angles

2a+110=180(co interior angle)

2a=180-110

a=70/2=35

2a=2×35=70

a=x=35 alternate angle

x+2a=y exterior angle of triangle is equal to the sum of two interior angle

35+70=y

y=105

x=a

(being alternate angles)

x+2a=110°

(Being sum of interior angles opposite to exterior angles)

or, a +2a =110°

or, 3a=110°

or, a=110°/3

therefore, a=36.67

Now;

2a = 2×36.67

= 73.34

the answer I solved is wrong please don't write it

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.

answer: apothems is your answer

step-by-step explanation: hope u get it right