The graph of y=ax squared is wider than the graph of y=x squared when 0<|a|< 1 this statement is sometimes always or never true

each side has a different length.  

step-by-step explanation:

60 for the first and 130 for the second

step-by-step explanation:

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)