What is a way that i can get 3x and 2x to cancel out in this problem? i need to get - 5y = -13 and + 15y = -3 alone. problem:
3x + 5y = -13
2x + 15y= 3

For 3x + 5y = -13 the answer is x= -13/3 + 5y/3

and for 2x + 15y=3 the answer x= 1.5 + (-15y/2)

Step-by-step:

For 3x+5y=-13 you have to add 5y on both sides. Then you have to divide by 3 on both sides and cancel out the common factor of 3. Then you would get x= 13/3 + 5y/3.

For 2x + 15y=3 you have to subtract 15y on both sides of the equation. You should have 2x=3 + (-15y). Then divide by 2 on both sides. 3 divided by 2 is 1.5 and -15y divided by 2 is -15y/2 since 2 doesn't have the same variable. so the answer should be x= 1.5 + (-15y/2).

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)