4. The first step of this trick was to pick a number between 1 and 10. You probably assumed that this meant to pick a counting number: 1,2,3,4,5,6,
7,8,9, or 10

a. Would this trick work if a person picked a decimal number between
1 and 10, such as 2.5 or 4.75? How do you know?

b. Would it work if they picked a number greater than 10 or less than
0? How do you know?

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

4x and 6y

im not sure though

i would be happy to . most people on would also love to i'm sure. if you just want someone who has done algebra before and want a little more personal relationship than just begging strangers for , i can certainly be of service. i do have college myself so i might not be 24/7.