Someone please help me on this . I need the work too!!

Student ticket: $2

Adult ticket: $5

Step-by-step explanation:

1. Setting up the system of equations

let x be the cost for a child

let y be the cost for an adult

For the monday, that would be:

33x + 42y = 276

For the tuesday, you ahve

46x + 40y = 292

2. Solving

First, simplify each equation

33x + 42y = 276

To get all the numbers smaller divide both sides by 3

11x + 14y = 92

Do the same for the other equation:

46x + 40y = 292

divide both sides by 2

23x + 20y = 146

You want to use elimination, so take the equation 11x + 14y = 92 and multiply both sides by 10

110x + 140y = 920

Take the equation 23x + 20y = 146 and multiply both sides by 7

161x + 140y = 1022

Subtract the two equations:

110x + 140y = 920

- (161x + 140y = 1022)

-51x = -102

divide both sides by -51

x = 2

Plug this into the original equation, 11x + 14y = 92:

11 * 2 + 14y = 92

22 + 14y = 92

subtract 22 from both sides

14y = 70

divide both sides by 14

y = 5

So the cost of a student ticket is $2 and the cost of an adult ticket is $5

b. ol

step-by-step explanation:

i got the answer right on edg.

congruent: (geometry) (of figures) identical in form; coinciding exactly when superimposed.