Shaun's tent (shown below) is a triangular prism.

52.8

Step-by-step explanation:

Let's draw a net of the tent.

Hint #22 / 5

333 of the faces are 555 by 333 rectangles.

\begin{aligned} \text{Area of a rectangle} &= \text{length} \cdot \text{width} &= 5 \cdot 3 &= {15} \end{aligned}

Area of a rectangle

​

=length⋅width

=5⋅3

=15

​

The total area of these 333 rectangles is 3 \cdot 15 = \blueE{45}3⋅15=453, dot, 15, equals, start color #0c7f99, 45, end color #0c7f99.

Hint #33 / 5

222 of the faces are triangles. Each triangle has the same base and height.

\begin{aligned} \text{Area of a triangle} &= \dfrac12 \cdot \text{base} \cdot \text{height} &= \dfrac12 \cdot 3 \cdot 2.6 &= 3.9 \end{aligned}

Area of a triangle

​

=

2

1

​

⋅base⋅height

=

2

1

​

⋅3⋅2.6

=3.9

​

The total area of these 222 triangles is 2 \cdot 3.9 = \goldE{7.8}2⋅3.9=7.82, dot, 3, point, 9, equals, start color #a75a05, 7, point, 8, end color #a75a05.

Hint #44 / 5

Let's add the areas we found to find the surface area.

\begin{aligned} \text{Surface area} &= \blueE{45}+ \goldE{7.8} &= 52.8 \end{aligned}

Surface area

​

=45+7.8

=52.8

​

Hint #55 / 5

The surface area of the tent is 52.8\text{ m}^252.8 m

2

52, point, 8, start text, space, m, end text, squared.

just find the gcf and solve the gcf's until you get each answer i have a really good feeling somethings missing xd (like the dimensions of the fence) *cough *cough *hint *hint

step-by-step explanation: