Mathematics, 25.02.2021 21:50 haftjnd9156
We can now solve 1 + u = ±Ket2/2 + 6t for u. u = −1 ± Correct: Your answer is correct. , where K > 0 Notice that u = −1 is a solution. This means that K could also be 0. Since we now know that K ≥ 0 we can let A represent any arbitrary constant and replace ±K with +A to create a more simplified equation. So we could simply write
Answers: 2
Mathematics, 21.06.2019 20:00
Pepe and leo deposits money into their savings account at the end of the month the table shows the account balances. if there pattern of savings continue and neither earns interest nor withdraw any of the money , how will the balance compare after a very long time ?
Answers: 1
Mathematics, 22.06.2019 00:00
The cost of a taxi ride includes an initial charge of $2.00. if a 5km ride cost $6.00 and a 10km ride cost $10.00, determine the cost of a 15km ride.
Answers: 1
Mathematics, 22.06.2019 00:30
Astudent was asked to find the square of 7x+3. the student quickly wrote (7x+3)^3= 49x^2+9. identify the student's error and provide the correct answer.
Answers: 3
We can now solve 1 + u = ±Ket2/2 + 6t for u. u = −1 ± Correct: Your answer is correct. , where K >...
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