25 points and brainliest will be given! To entertain her children on one of many snow days, Mrs. French built a snowball catapult, which she mounted to the backyard deck. The deck is 20ft above the ground. If a snowball is launched with an inital velocity of 64ft per second, the height of the snowball above the groun(h), (t) seconds after it is launched is given by h= -16t^2+64t+20. A squirrel is sitting on a branch 68ft above the ground.
How many second after the snowball is launched will it pass by the squirrel on the way back down?

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

i would need to see the dot plot : )

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!