Solve the system by substitution.
3x-6y=2
4x+3y=-1​

y = -1/3

x = 0

Step-by-step explanation:

3x-6y = 2    then 3x = 2+6y,   x=(2+6y)/3

4x+3y = -1

substitute for x

4(2/3+2y)-6y = 2

8/3+8y-6y = 2

reduce

2y = 2-8/3

2y = -2/3

divide both sides by 2

y = -1/3

4x+3(-1/3) = -1

4x = 0

x = 0

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol