The line is parallel to y = -3x - 2 and passes through the point (-4, 3)

y = -3x - 9

Step-by-step explanation:

Parallel lines have same slope.

y = mx + b

m -> slope & b ->y-intercept

y = -3x - 2

So, slope of the required line = -3

(-4 , 3)

y -  y1 = m(x - x1)

y - 3 = -3(x - [-4])

y - 3 = -3(x + 4)

y - 3 = x*(-3) + 4*(-3)

y - 3 = -3x - 12

     y = -3x -12 + 3

     y = -3x - 9

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.