PLZ HELPOn a coordinate plane, 5 squares are shown. Square L M N P has points (negative 3, 1), (negative 1, 1), (negative 1, negative 1), (negative 3, negative 1). Square 1 has points (negative 6, 4), (negative 6, 6), (negative 4, 6), (negative 4, 6). Square 2 has points (negative 6, negative 4), (negative 6, negative 6), (negative 4, negative 4), (negative 4, negative 6). Square 3 has points (2, 2), (2, 4), (4, 4), (4, 2). Square 4 has points (2, negative 2), (4, negative 2), (4, negative 4), (2, negative 4). Assume each figure shown has the same orientation. Which figure is the image of square LMNP after a translation of (x, y) → (x + 5, y – 3)?

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.