A car depreciates at a rate of 15% of its value annually. Carl purchased a new car for $25,000 and wants to know how many years it will take until the car is worth a specific amount.
a) Formulate a logarithmic function that would find the number of years t it will take for the car to be worth x dollars.
Then
b) How many years will Carl have until he new car is worth about $5000?

(a) (log X - log 25000)/log 0.85 = t

(b) about 9.9 years

Step-by-step explanation:

(a)   Let X = value and t = elapsed years since purchase; X in dollars

X = 25000 x 0.85 x 0.85 x 0.85 ... with a factor of 0.85 for every year

(If you lose 15% of value, you have 85% left, right?)

So if you do it for t years, you have t as the exponent on the 0.85 factor.

 is a good equation, but not logarithmic like they ask.

   because the log of a product is the sum of the logs of the factors

log X = log 25000 + t*log 0.85  because the log of a power is power times log

log X - log 25000 = t* log 0.85    just algebra, subtracting from both sides

(log X - log 25000)/log 0.85 = t   just algebra, dividing both sides

(b)  If we let X = $5000

t = (log 5000 - log 25000)/log 0.85

 = (3.69897 - 4.39794)/-0.07058

 =  9.90

So t = 9.9 years is a good estimate

1; 35 is the ratio

step-by-step explanation:

18.75 gallons

step-by-step explanation: