What is the first step to solving this 2 step equation. 3x + 8 = 29

3x/3x + 8 = 29/3x
3x + 8 - 8 = 29 - 8
3x/3 + 8 = 29/3
3x /3= 21/3

Subtract 8 from both sides

Step-by-step explanation:

3x + 8 - 8 = 29 - 8

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

i pretty sure it is