Evaluate 3a+15+bc−6, when a=7, b=3, and c=15.

Enter your answer in the box.

3(7)+15+(3)(15)-6

21+15+45-6=75

=37 hope this is right

The full question isn’t shown. part of it is cut off

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.