An arrow is shot at 30.0° above the horizontal. Its velocity is 49 m/s, and it hits the target. What is the maximum height the arrow will attain?

30.625 m

Step-by-step explanation:

Maximum Height :

(u²sin²θ) / 2g

u = 49 m/s

θ = 30°

g = 9.8m/s

(49² * 0.5²) / 2 * 9.8

600.25 / 19.6

= 30.625 m

step-by-step explanation:

what is the figure? attach a picture.

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.