Ile to potrzebuje działania !! (12x + 2y-5) + (6y-12x + 9)

- (3x + 9) - (12 + 8x)

12 - (- 6x + 12) + 36x

14+ (3x-9) - (5x + 11)

- (- 7x + 15) - (- 8 + 4x)

16 + 2x + (8x-26)

14x + 36- (9 + 36)

- (8z + 11) + 8z

3x- (12-9x)

- (7x + 9)

-9-18+ (21x-9)

(64x + 5) + (8x-9)

- (36x-1) + (36x-1)

- (5x + 5) + 12x

(8x-9) + ( 9x-8)

Ile to potrzebuje działania !!

(12x + 2y-5) + (6y-12x + 9)

- (3x + 9) - (12 + 8x)

12 - (- 6x + 12) + 36x

14+ (3x-9) - (5x + 11)

- (- 7x + 15) - (- 8 + 4x)

16 + 2x + (8x-26)

14x + 36- (9 + 36)

- (8z + 11) + 8z

3x- (12-9x)

- (7x + 9)

-9-18+ (21x-9)

(64x + 5) + (8x-9)

- (36x-1) + (36x-1)

- (5x + 5) + 12x

(8x-9) + ( 9x-8)

Step-by-step explanation:

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step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v