A submarine travels at an elevation of -75 3/4 ft relative to sea level. Then its elevation changes by -16 3/8 ft. What is the new elevation of the submarine? Show your work

The new navigation height of the submarine is -62.25 feet.

Step-by-step explanation:

Given that a submarine travels at an elevation of -75 3/4 ft relative to sea level, and then its elevation changes by -16 3/8 ft, to determine what is the new elevation of the submarine the following calculation must be performed:

3/4 ft = 0.75 ft

-75 x 0.75 = -56.25 ft

3/8 ft = 0.375 ft

-16 x 0.375 = -6 ft

-56.25 + -6 = -62.25

Thus, the new navigation height of the submarine is -62.25 feet.

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x