A recent survey of students at John Tukey High School revealed that 18% of the students are in favor of changing the dress code. If you ran-
domly select 15 students from this school, what is the probability that
at least three of these students are in favor of the proposal to change the
dress code?

0.5234 = 52.34% probability that at least three of these students are in favor of the proposal to change the dress code.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they are in favor, or they are not. Students are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

18% of the students are in favor of changing the dress code.

This means that

You randomly select 15 students

This means that

What is the probability that at least three of these students are in favor of the proposal to change the dress code?

This is

In which

In which

0.5234 = 52.34% probability that at least three of these students are in favor of the proposal to change the dress code.

one of each metals

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)