Alandscaper mows lawns for at least 3 hours but not more than 6 hours. the landscaper can mow 44,000 ft2 per hour. the function f(t)=44,000t represents the number of square feet the landscaper can mow in t hours.
what is the practical range of the function?
all real numbers
all multiples of 44,000 between 132,000 and 264,000, inclusive
all real numbers from 3 to 6, inclusive
all real numbers from 132,000 to 264,000, inclusive

- Fourth options is correct. The practical range of the function = all real numbers from 132,000 to 264,000, inclusive.

Explanation:-

Given function : , represents the number of square feet the landscaper can mow in t hours.

A landscaper mows lawns for at least 3 hours but not more than 6 hours.

⇒ 3 ≤ t ≤ 6

⇒ The practical range of the function = f(3) ≤ f(t) ≤ f(6)

Now, f(3)= 44,000(3)=132,000 sq. ft.

f(6)=44,000(6)=264,000 sq. ft.

Thus, The practical range of the function = 132,000 sq. ft.≤ f(t) ≤ 264,000 sq. ft.

⇒The practical range of the function = all real numbers from 132,000 to 264,000, inclusive.

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25

required rate of return = 0.166 = 16.6%

step-by-step explanation:

under the capital asset pricing model (capm), the required or expected rate of return for a particular security or asset is given using the formula:

required rate of return = risk-free rate + beta*(market risk premium)

we are given that;

risk-free rate = 4% = 0.04

beta = 1.4

market risk premium = 9% = 0.09

we simply plug these values into the above formula;

required rate of return = 0.04 + 1.4*(0.09)

required rate of return = 0.04 + 0.126

required rate of return = 0.166 = 16.6%