A line that is perpendicular to y=-3x-10 passing through the point (6,8)

y = -1/3x + 10

Step-by-step explanation:

To make it perpendicular change the reciprocals

So instead of 3x it'll be -1/3x and so it passes through the given points

plug the points

8 = -1/3(6) + b

8 = -2 + b

add 2 to both sides

10 = b

so the equation of a line thats perpendicular to y=-3x-10 and passes through

points (6,8) is

y = -1/3x + 10

do it yourself this is easy

step-by-step explanation:

1. 180°. the sum of the interior angles of a triangle is 180°, for the equilateral triangle that it has three equals side is 60°+60°+60°=180°.

2. 60°. each interior angle of a equilateral triangle is 60°

3. 120°. the measure of ∠m is 120°, the sum of the angles ∠m and ∠n is equal to 180°. so, in order to find the measure of ∠m, we have ∠m+∠n=180° > ∠m=180°-∠n > ∠m=180°-60°=120°.

4. 360°. the sum of the exterior angles of an equilateral triangle is ∠m+∠r+∠x=120°+120°+120°=360°. the exterior angles of any triangle always add 360°.