Write a quadratic equation could some please help asap​

f(x) = x^2 + 3x + 2.

Step-by-step explanation:

The zeroes of the quadratic function are -1 and -2 so we can write it as:

f(x) = a(x + 1)(x + 2)    where  a is some constant.

Now, when x = 1,  f(x) = 6 so

6 = a(1+1)(1+2)

6 = a*2*3 = 6a

a = 1.

So the function is f(x) = (x + 1)(x + 2) = x^2 + 3x + 2.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180