Help please! brainiest to best answer! <3 Kayson is looking at two buildings, building A and building B, at an angle of elevation of 40°. Building A is 120 feet away, and building B is 60 feet away. Which building is taller and by approximately how many feet?

Building A; it is around 100.69 feet taller than building B
Building A; it is around 50.34 feet taller than building B
Building B; it is around 100.69 feet taller than building A
Building B; it is around 50.34 feet taller than building A

Hello! Here your answer!...

The buildind B is taller, by approximately 33.286 feet

Step-by-step explanation:

To find the height of the buildings, we can use the tangent relation of the angle of elevation. The opposite side is the height of the building, and the adjacent side is the distance to the building:

Using h_A to the height of building A and h_B to the height of building B, we have:

tan(59) = h_A / 40

1.6643 = h_A / 40

h_A = 66.572 feet

tan(59) = h_B / 60

1.6643 = h_B / 60

h_B = 99.858 feet

The buildind B is taller, by approximately (99.858 - 66.572) = 33.286 feet

Hope this helps!♥

Building A; it is around 50.34 feet taller than building B

Step-by-step explanation:

hope this help

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