PLEASE HELP ME!!
Prove that ΔABC and ΔEDC are similar.
15 over 5 equals 12 over 4 equal...
Mathematics, 23.02.2021 21:20 alee885
PLEASE HELP ME!!
Prove that ΔABC and ΔEDC are similar.
15 over 5 equals 12 over 4 equals 9 over 3, shows the corresponding sides are proportional; therefore, ΔABC ~ ΔEDC by the SSS Similarity Postulate.
∠DCE is congruent to ∠CBA by the Vertical Angles Theorem and 15 over 5 equals 12 over 4 shows the corresponding sides are proportional; therefore, ΔABC ~ ΔEDC by the SSS Similarity Postulate.
∠E and ∠B are right angles and, therefore, congruent since all right angles are congruent. 9 over 4 and 12 over 3 shows the corresponding sides are proportional; therefore, ΔABC ~ ΔEDC by the SAS Similarity Postulate.
15 over 4 equals 12 over 5 equals 9 over 3 shows the corresponding sides are proportional; therefore, ΔABC ~ ΔEDC by the SAS Similarity Postulate.
Answers: 1
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