Which linear any qualities could represent the given table of values

The answer is (B) y ≤ –2x + 3 .

Step-by-step explanation: We are to select the correct linear inequality that could represent the table of values given in the question.

If (x, y) = (-4, -1), then

\begin{gathered}y=-1,-2x+3=-2\times(-4)+3=8+3=11.\end{gathered}

y=−1,

−2x+3=−2×(−4)+3=8+3=11.

So, y < -2x + 3.

If (x, y) = (-2, 4), then

\begin{gathered}y=4,-2x+3=-2\times(-2)+3=4+3=7.\end{gathered}

y=4,

−2x+3=−2×(−2)+3=4+3=7.

So, y < -2x + 3.

If (x, y) = (3, -3), then

\begin{gathered}y=-3,-2x+3=-2\times 3+3=-6+3=-3.\end{gathered}

y=−3,

−2x+3=−2×3+3=−6+3=−3.

So, y = -2x + 3.

If (x, y) = (3, -4), then

\begin{gathered}y=-4,-2x+3=-2\times 3+3=-6+3=-3.\end{gathered}

y=−4,

−2x+3=−2×3+3=−6+3=−3.

So, y < -2x + 3.

Therefore, we have y is either less than or equal to (-2x + 3).

Thus, y ≤ –2x + 3 and (B) is the correct option.

answer: 2 and 1

step-by-step explanation: got this question

cosine

step-by-step explanation: