Write an equation of the line that passes through the given point and is parallel to the given line. (2, -3); y = –5

y = -3

Step-by-step explanation:

The given line is a horizontal line thru -5 on the y-axis.

Your line is parallel to y = -5, hence is also a horizontal line and passes thru (2, -3).  Since -3 is the y-coordinate of that point, y = -3 is the equation of the line you are looking for.

what's the question?

step-by-step explanation:

there is no question.

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9